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qid 9451 · physics
Question: A steel ball of velocity $5 \mathrm{~m} / \mathrm{s}$ strikes a smooth, heavy steel plate at an angle of $30^{\circ}$ from the normal. If the coefficient of restitution is 0.8 , at what velocity does the steel ball bounce off the plate?
- $4.8$$\mathrm{~m} / \mathrm{s}$
- $3.8 \mathrm{~m} / \mathrm{s}$
- $4.3$$\mathrm{~m} / \mathrm{s}$
- $4.0 \mathrm{~m} / \mathrm{s}$
- $3.5$$\mathrm{~m} / \mathrm{s}$
- $4.6 \mathrm{~m} / \mathrm{s}$
- $2.5 \mathrm{~m} / \mathrm{s}$
- $5.0$$\mathrm{~m} / \mathrm{s}$
- $3.2 \mathrm{~m} / \mathrm{s}$
- $2.8 \mathrm{~m} / \mathrm{s}$
Our answer: C. $4.3$$\mathrm{~m} / \mathrm{s}$ Source quote machine-checked (exact quote)
How it was answered
Multi-step solver (maze), replayed by code
Current source
Wikipedia, Coefficient of restitution
https://en.wikipedia.org/wiki/Coefficient_of_restitution
“The coefficient of restitution can be thought of as a measure of the extent to which energy is conserved when an object bounces off a surface.”
Source quote machine-checked (exact quote)
Earlier version (superseded)
https://en.wikipedia.org/wiki/Coefficient_of_restitution
Source weak (http_get_200_text_and_question_terms)
Earlier version (superseded)
No public source has been found for this card yet (3 places checked internally).
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