Substrate Record: qid 8052

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qid 8052 · math

Question: Rewrite the expression $6j^2 - 4j + 12$ in the form $c(j + p)^2 + q$, where $c$, $p$, and $q$ are constants. What is $\frac{q}{p}$?

1. -3
2. 38
3. 34
4. -34
5. 11
6. 0
7. 3
8. -38
9. -1
10. -11

Our answer: D. -34 Source pending

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