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qid 8010 · math
Question: A soft drink dispenser can be adjusted to deliver any fixed number of ounces. If the machine is operating with a standard deviation in delivery equal to 0.3 ounce, what should be the mean setting so that a 12-ounce cup will overflow less than 1% of the time? Assume a normal distribution for ounces delivered.
- 12 + 0.99(0.3) ounces
- 12 - 1.645(0.3) ounces
- 12 + 2.326(0.3) ounces
- 12 - 1.96(0.3) ounces
- 12 + 2.576(0.3) ounces
- 12 + 1.645(0.3) ounces
- 12 - 0.99(0.3) ounces
- 12 - 2.576(0.3) ounces
- 12 + 1.96(0.3) ounces
- 12 - 2.326(0.3) ounces
Our answer: J. 12 - 2.326(0.3) ounces Source quote machine-checked (exact quote)
How it was answered
Multi-step solver (maze), replayed by code
Current source
NIST/SEMATECH e-Handbook of Statistical Methods, "Critical Values of the Standard Normal Distribution"
https://www.itl.nist.gov/div898/handbook/eda/section3/eda3671.htm
Source quote machine-checked (exact quote)
Earlier version (superseded)
https://www.itl.nist.gov/div898/handbook/eda/section3/eda3671.htm
Source weak (http_get_200_text_and_question_terms)
Earlier version (superseded)
No public source has been found for this card yet (3 places checked internally).