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qid 12179 · engineering
Question: An input signal v(t) =I\delta(t) (impulse function) is passed through a filter having function (1 - e-j\omega\tau)/j\omegawhere \tau is the stretchedumpulsewidth. Determine the output of the filter.
- v_o(t) = I [δ(t) * e^(-t/τ)]
- v_o(t) = I [e^(-jωt) - u(t - τ)]
- v_o(t) = I [1 - e^(-jωτ)]
- v_o(t) = I [u(t) / (u(t) + u(t - τ))]
- v_o(t) = I [u(t) / u(t - au)]
- v_o(t) = I [u(t) + u(t - au)]
- v_o(t) = I [u(t) * u(t - au)]
- v_o(t) = I [u(t) - u(t - au)]
- v_o(t) = I [δ(t) - e^(-t/τ)]
- v_o(t) = I [sin(ωt) * u(t - τ)]
Our answer: H. v_o(t) = I [u(t) - u(t - au)] Source quote machine-checked (exact quote)
How it was answered
Multi-step solver (maze), replayed by code
Current source
mbedded.ninja, "Windowed Moving Average Filters"
“A simple moving average filter can also be seen as a convolution between the input signal and a rectangular pulse whose area is 1.”
Source quote machine-checked (exact quote)
Earlier version (superseded)
https://en.wikipedia.org/wiki/Rectangular_function
Source weak (http_get_200_text_and_question_terms)
Earlier version (superseded)
No public source has been found for this card yet (3 places checked internally).
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