← back to the Substrate Record
qid 11773 · engineering
Question: A six-pole generator requires 4.5 amp shunt-field excitation to give rated voltage at no load, and 7.0 amp to give the same voltage at rated load of 200 amp. There are 750 shunt-field turns per pole. (a) How many series turns must be added to give flat-compound operation, using the short-shunt connection? (b) If 12 turns per pole are added, having a resistance of 0.005 ohm per pole, what should be the resistance of a shunt across the series- field terminals to give the desired flat-compound effect?
- 8.4, 0.095 ohm
- 8.4, 0.107 ohm
- 11.0, 0.110 ohm
- 9.4, 0.117 ohm
- 10.4, 0.107 ohm
- 9.0, 0.115 ohm
- 8.5, 0.100 ohm
- 9.4, 0.107 ohm
- 7.5, 0.120 ohm
- 10.4, 0.125 ohm
Our answer: H. 9.4, 0.107 ohm Source pending
Source pending. No public source has passed the machine check for this card yet.
Know a citable source for this fact? See the Research Marks bounty poster.
How it was answered
Multi-step solver (maze), replayed by code
Current source
No public source has been found for this card yet (3 places checked internally).